How to Solve the Diode Circuits (Explained with Examples)

How to Solve the Diode Circuits (Explained with Examples)

In this video, different methods for solving the diode circuits have been discussed.

There are two methods for solving/ analyzing the diode circuits.
1) Graphical Method
2) Diode Approximation

Both methods have been discussed in the video and using the diode approximation method, different circuit problems have been solved.

The timestamps for the different topics covered in the video:

1:02 Graphical Method (Using the Load Line)

3:19 Diode Approximations

4:29 How to Solve a circuit problem using diode approximation

7:46 Example 1 ( Series connection of Diode)

9:54 Example 2

12:11 Example 3 (Parallel Connection of Diode)

13:41 Example 4 (Parallel Connection of Diode with different diodes (Si and Ge))

16:11 Example 5 (Parallel connection of diode with different voltages)

Graphical Method:
In graphical method, the load line is drawn on the V-I curve of the diode.
The load line gives the possible values of voltage and current of the diode for the given circuit. The intersection of the V-I curve of the diode and the load line gives the operating voltage and current of the diode.

Diode Approximation:
In the diode approximation, the diode is replaced by the equivalent circuit. Although the values of voltage and current of the diode by this method is not exact, using the diode approximation the circuits can be solved/ analyzed very easily.

The link for the other useful videos related to diode:
1) Introduction to a diode and V-I characteristics of the diode

2) The diode resistance Explained:

This video will be helpful to all students of science and engineering in learning how to solve the diode circuit problems.

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50 Comments

  1. prince kumar on January 18, 2019 at 7:28 pm

    4 v across in 1k

  2. Amani Alzhrany on January 18, 2019 at 7:29 pm

    This is really helpful .. Thank you

  3. alex maie on January 18, 2019 at 7:29 pm

    4 !!!

  4. Pravallika Goud K E on January 18, 2019 at 7:30 pm

    sir 4 volt answer is it correct?

  5. Naresh Naresh on January 18, 2019 at 7:31 pm

    Why we can’t choose 2v-0.7 as vo last question

  6. Vignesh Theshield on January 18, 2019 at 7:31 pm

    Sir example 5 you missed the -1v so you wrote vo is 3.3, sir I thick vo is 4.3v or is vo across the second node only

  7. kiran bibi on January 18, 2019 at 7:33 pm

    Sir plz send me your whats app no mera kal boht important asigmnt hai mere face book ud nahe hai me kise karo

  8. diptimandas1 on January 18, 2019 at 7:33 pm

    Ye sab jee mains mein aata hain kya???

  9. Mitzi Jones on January 18, 2019 at 7:36 pm

    This really helped. Thanks!

  10. Akhil Marisetti on January 18, 2019 at 7:36 pm

    Worthful video

  11. Saiprakash Putrevu on January 18, 2019 at 7:39 pm

    Nice explanation sir…

  12. prathumna radhakrishnan on January 18, 2019 at 7:39 pm

    In ex.5 you calculated that V0=4-0.7. but there is a negative voltage of -1v also. Then can i say v0=(4-0.7-0.1)volt

  13. Ritwik Raj on January 18, 2019 at 7:40 pm

    In example 4, why did you take output voltage equal to 0.7

  14. MS MINI FUTURE TECH on January 18, 2019 at 7:42 pm

    In last question why are we assuming that 2nd diode is conducting only

  15. Jovan Ramadhan on January 18, 2019 at 7:43 pm

    sir i didnt get it when you explained to me about vo at 12:02 why it has to be vo=v2-5? thanks sir

  16. Manjunath Manju on January 18, 2019 at 7:44 pm

    I am not understanding

  17. Danial Roslan on January 18, 2019 at 7:44 pm

    sir, on example 4, on finding the Vo, why is V2-5V?

  18. Glen max prathap on January 18, 2019 at 7:47 pm

    CURRENT FLOWING IN CIRCUIT IS 4ma & voltage across the diode is 4v in given ciruit

  19. Yo Ming on January 18, 2019 at 7:47 pm

    i learned a lot from you thankyou from algeria

  20. Yasmine Kudjoe on January 18, 2019 at 7:47 pm

    I was so confused with this diodes stuff but you saved my llife. Thank you, you are the best

  21. Altair Is Here on January 18, 2019 at 7:49 pm

    You are life saver!!!!πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘

  22. sizwe nhlanhla on January 18, 2019 at 7:50 pm

    thank you,well and clear!!!!!!!!!!!!!!

  23. kiran bibi on January 18, 2019 at 7:52 pm

    Sir me ap ko istarh ak pic send kardonge mera kal both zarore assigmnt hai plz

  24. Tatipally venkat Akhila reddy on January 18, 2019 at 7:55 pm

    4.mA,4

  25. Mostafa Elgayar on January 18, 2019 at 7:55 pm

    I think on 9:35, you meant 2.9 volts not 2.1 volts, am I right?

  26. Abdoulaye Balde on January 18, 2019 at 7:55 pm

    I = 4mA and v=4v .am i correct sir?

  27. K on January 18, 2019 at 7:58 pm

    thanks alot

  28. ALL ABOUT ELECTRONICS on January 18, 2019 at 7:58 pm

    The timestamps for the different topics covered in the video:

    1:02 Graphical Method (Using the Load Line)

    3:19 Diode Approximations

    4:29 How to Solve a circuit problem using diode approximation

    7:46 Example 1 ( Series connection of Diode)

    9:54 Example 2

    12:11 Example 3 (Parallel Connection of Diode)

    13:41 Example 4 (Parallel Connection of Diode with different diodes (Si and Ge))

    16:11 Example 5 (Parallel connection of diode with different voltages)

  29. Momodou Lamin drammeh on January 18, 2019 at 7:58 pm

    Tamam… Your explanations are always Crystal Clear…

  30. Ashad Khan on January 18, 2019 at 7:59 pm

    Example 5 is not clear ,u assumed that 2nd diode is working.On that basic u solve it .Why didnt assume that 1st diode is working

  31. Glen max prathap on January 18, 2019 at 7:59 pm

    nice video

  32. Jared Cruz on January 18, 2019 at 8:01 pm

    Excellent video. Very clear and helpful.

  33. Righteous Ness on January 18, 2019 at 8:02 pm

    good teaching, thank you.

  34. TheUltimateFreezone7 on January 18, 2019 at 8:03 pm

    My niggggggaaaa

    Great explanation g.

  35. MATHEMATICS GURU on January 18, 2019 at 8:03 pm

    In example 5 why the second diode can’t be OFF and Ist one ON?
    please explain it…..

  36. Salman Sabbir on January 18, 2019 at 8:07 pm

    Thank’s Sir. It’s the best tutorial. After watching this tutorial, nobody else has any problem, I think.

  37. MUZTAHID ISLAM on January 18, 2019 at 8:08 pm

    Sir , thanks for informative video , sir I have questions , that’s I have two different DC source ,now I want to add these source by using diode ,so how will connect two different sources . ? Please answer me .

  38. Nimra Aziz on January 18, 2019 at 8:12 pm

    Can u please explain if two diods are parallel but in reverse direction at that time how much Vout we get and why??

  39. Ansh Maurya on January 18, 2019 at 8:14 pm

    How can we say that the assumption is right in example 5?

  40. abdou rashad on January 18, 2019 at 8:14 pm

    good work

  41. Raymond Lewis on January 18, 2019 at 8:15 pm

    Needs English subtitles.

  42. Sudarsana Reddy on January 18, 2019 at 8:15 pm

    Tq

  43. manu on January 18, 2019 at 8:16 pm

    I didn’t understood the last one .how u told it is 4 volt

  44. Dev Guy on January 18, 2019 at 8:18 pm

    @ 17:32 did you just assume 4V circuit to be on to solve? or is it the case that if both path are powered, only the path with 4V will turn on.

  45. yuvraj pradhan on January 18, 2019 at 8:18 pm

    sir pls make a vid about smart phone PCB and SENSORS explains its parts

  46. sumit pundir on January 18, 2019 at 8:19 pm

    Voltage across 1 kilo ohm resistance is equals to 4 volt

  47. Kyle de la O on January 18, 2019 at 8:20 pm

    The voltage across the 1k ohm resistor is 4 V and the current for the circuit is 4 mA for the example with one silicon diode and one germanium diode.

  48. akleshkumar tendulkar on January 18, 2019 at 8:25 pm

    4mA ,4v

  49. Venus Jain on January 18, 2019 at 8:26 pm

    Kathode

  50. shravan gatty on January 18, 2019 at 8:26 pm

    I=4mA
    Vo=4v

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